3w^2+5w=232

Solution for 3w^2+5w=232 equation:

3w^2+5w=232

We move all terms to the left:

3w^2+5w-(232)=0

a = 3; b = 5; c = -232;
Δ = b2-4ac
Δ = 52-4·3·(-232)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-53}{2*3}=\frac{-58}{6}
=-9+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+53}{2*3}=\frac{48}{6}
=8
$